Use of the internet for shopping is increasing​ dramatically, but still is somewhat age dependent. When a popular web site that sells books asked the age of users who bought products from them over the​ internet, they obtained the following data. What is the probability that a buyer on this web site is aged 60 dash 69 question mark

Question

Start 8 By 2 Table 1st Row 1st Column Age Group 2nd Column Number 2nd Row 1st Column 10 minus 19 2nd Column 1 comma 981 3rd Row 1st Column 20 minus 29 2nd Column 3 comma 809 4st Row 1st Column 30 minus 39 2nd Column 2 comma 805 5st Row 1st Column 40 minus 49 2nd Column 890 6st Row 1st Column 50 minus 59 2nd Column 437 7st Row 1st Column 60 minus 69 2nd Column 364 8st Row 1st Column 70 minus 79 2nd Column 68 EndTable

Answer 1

To calculate the probability that a buyer on the website is aged 60-69, we need to use the total number of buyers and the number of buyers in that age group.

Here’s a breakdown of the data provided:

• Age 10-19: 1,981
• Age 20-29: 3,809
• Age 30-39: 2,805
• Age 40-49: 890
• Age 50-59: 437
• Age 60-69: 364
• Age 70-79: 68

Now, let's calculate the total number of buyers:

\[ \text{Total} = 1981 + 3809 + 2805 + 890 + 437 + 364 + 68 \]

Calculating the total:

\[ 1981 + 3809 + 2805 + 890 + 437 + 364 + 68 = 1981 + 3809 = 5790 \] \[ 5790 + 2805 = 8595 \] \[ 8595 + 890 = 9485 \] \[ 9485 + 437 = 9922 \] \[ 9922 + 364 = 10286 \] \[ 10286 + 68 = 10354 \]

So, the total number of buyers is 10,354.

Next, we find the number of buyers aged 60-69, which is 364.

Now, we can calculate the probability:

\[ P(\text{60-69}) = \frac{\text{Number of buyers aged 60-69}}{\text{Total number of buyers}} = \frac{364}{10354} \]

Calculating this:

\[ P(\text{60-69}) = \frac{364}{10354} \approx 0.0351 \]

Thus, the probability that a buyer on this website is aged 60-69 is approximately 0.0351, or 3.51%.