You want f(x) = 0 where f(x) = x^2 - x - √(x+1)
f'(x) = 2x - 1 - 1/(2√(x+1))
so start with x=1 and see what happens
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keisan.casio.com/exec/system/1244946907
Use Newton's method to find all solutions of the equation correct to six decimal places. (Enter your answers as a comma-separated list.)
sqrt(x + 1) = x^2 − x
x = ?
1 answer
2 answers