Use multiplication to find the product that demonstrates the Closure Property of multiplication of polynomials. (1/2 x^2 - 3) (4y^3 + 5x^2)

A, √x^2y^3 + 4x^4-15^2

B, 2x^2y^3 + 5/2x^4 - 12y^3 - 15x^2

C, 5/2x^2y^3 + 2x^4 - 8y^3 + 15x^2

D, x^2y^3 + 2x^4 - 8y^3 - 15x^2

1 answer

To demonstrate the Closure Property of multiplication of polynomials, we will multiply the two polynomials \( (1/2 x^2 - 3) \) and \( (4y^3 + 5x^2) \).

Let's compute the product step by step:

  1. Distribute \( (1/2 x^2) \) across \( (4y^3 + 5x^2) \): \[ (1/2 x^2)(4y^3) + (1/2 x^2)(5x^2) = 2x^2y^3 + \frac{5}{2}x^4 \]

  2. Distribute \( (-3) \) across \( (4y^3 + 5x^2) \): \[ -3(4y^3) - 3(5x^2) = -12y^3 - 15x^2 \]

  3. Combine all the terms from both distributions: \[ 2x^2y^3 + \frac{5}{2}x^4 - 12y^3 - 15x^2 \]

Thus, the complete product can be written as: \[ 2x^2y^3 + \frac{5}{2}x^4 - 12y^3 - 15x^2 \]

Now, let's compare this with the given options:

A) \( \sqrt{x^2y^3 + 4x^4 - 15^2} \)

B) \( 2x^2y^3 + \frac{5}{2}x^4 - 12y^3 - 15x^2 \)

C) \( \frac{5}{2}x^2y^3 + 2x^4 - 8y^3 + 15x^2 \)

D) \( x^2y^3 + 2x^4 - 8y^3 - 15x^2 \)

The correct option is:

B) \( 2x^2y^3 + \frac{5}{2}x^4 - 12y^3 - 15x^2 \).