Use inspection to solve the equation x2=36169

x
2
=
36
169
, then select the correct solution set below. If there are no real solutions, select “There are no real solutions.”(1 point)
Responses

{−613}
{

6
13
}
left brace negative Start Fraction 6 over 13 End Fraction right brace

{613}
{
6
13
}
left brace Start Fraction 6 over 13 End Fraction right brace

{−613,613}
{

6
13
,
6
13
}
left brace negative Start Fraction 6 over 13 End Fraction comma Start Fraction 6 over 13 End Fraction right brace

There are no real solutions.

5 answers

To solve the equation \( x^2 = 36169 \) using inspection, we need to find the values of \( x \) such that when squared, they equal 36169.

  1. Take the square root of both sides of the equation: \[ x = \pm \sqrt{36169} \]

  2. Calculate \( \sqrt{36169} \): \[ \sqrt{36169} = 189 \]

  3. Therefore, the solutions for \( x \) are: \[ x = 189 \quad \text{and} \quad x = -189 \]

Thus, the solution set is: \[ {-189, 189} \]

From your options, the correct choice that represents this is: \({-613, 613}\)

However, it appears that the correct values you'd mentioned as options were incorrect (they should be -189 and 189). Thus, the final answer reflecting the calculated solutions is: \({-189, 189}\) would be the accurate solution set.

whats thw answer

The correct solution set for the equation \( x^2 = 36169 \) is:

\({-189, 189}\)

If that option is not available in your provided choices, please double-check as the correct solutions are \(-189\) and \(189\). If those specific options are not listed, let me know!

your wrong

I apologize for any confusion in my previous responses. Let's clarify the calculations.

To solve the equation \( x^2 = 36169 \):

  1. Calculate the square root of both sides: \[ x = \pm \sqrt{36169} \]

  2. Finding \( \sqrt{36169} \): \[ \sqrt{36169} = 189 \]

This gives: \[ x = 189 \quad \text{or} \quad x = -189 \]

Given these values, the correct solution set is: \[ {-189, 189} \]

If this doesn't match the answer choices you've provided, please let me know the exact choices again so we can accurately determine the response.

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