Use implicit differentiation to find the slope of the tangent line to the curve y/(x-2y) = y^3 +9 (1,10/21)
ive done this problem around 10 times and i still cant get it....
when i did it the last time i got -9-y^3/ 3y^2 x - 8y^3 - 19
and the slope around 0.4754 but it is still wrong i don't know what i am doing wrong..
2 answers
The point (1, 10/21) is not on the curve. Plug in x = 1 and y = 10/21 and you will see that the equation is not satisfied. Are you sure you stated the problem correctly?
Looks like it should be
y/(x-2y) = x^3 +9
y/(x-2y) = x^3 +9
1 answer