Question

Use Hess's law to calculate the enthalpy change for the reaction:
3C(s) + 3H2(g) ¡æ C3H6(g)

Given the following thermochemical equations:

2C3H6(g) + 9O2(g) ¡æ 6CO2(g) + 6H2O(l) ¥ÄH = -4116.0 kJ/mol

C(s) + O2(g) ¡æ CO2(g) ¥ÄH = -393.51 kJ/mol

H2(g) + ¨öO2(g) ¡æ H2O(l) ¥ÄH = -285.83 kJ/mol

please im soo confused!

Answer 1

I can't decipher the symbols, especially the coefficient for oxygen in the fourth equation (counting all equations you posted).