for 1 (4x-3)(x-2)
for 2 (3x-3)(3x-7)
use factoring and the zero-product property to solve
4a^2-11a+6=0
9r^2-30r+21=-4
2 answers
can you explain how you got that? i'm completely lost
4a^2-11a+6=0
9r^2-30r+21=-4
2 answers