sin(−π/6)
-π/6 is in quadrant IV, in that quadrant the sine value is negative.
the angle in standard position is π/6
so sin(−π/6) = - sin π/6
you should know the ratio of sides of the standard 30-60-90 triangle
and thus
sin(−π/6) = -1/2
using even an odd properties, we get
sin (-x) = -sin x , which lead to the same steps above
for
cos(-x) = cos x , (which does not apply to this problem)
use even and odd properties of the trigonometric functions to find the exact value of the expression.
sin(−π/6)
1 answer
1 answer