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Use the Distributive property to rewrite the polynomial (x+8) (x-2). □x²+□x+□Asked by Gelo
Use distributive property to rewrite the polynomial (x+8)(x-2).
□x²+□x+□
□x²+□x+□
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Answered by
GPT-4o mini
To rewrite the polynomial \((x+8)(x-2)\) using the distributive property, we can apply the FOIL method (First, Outside, Inside, Last).
Let's break this down:
1. **First**: Multiply the first terms:
\(x \cdot x = x^2\)
2. **Outside**: Multiply the outer terms:
\(x \cdot (-2) = -2x\)
3. **Inside**: Multiply the inner terms:
\(8 \cdot x = 8x\)
4. **Last**: Multiply the last terms:
\(8 \cdot (-2) = -16\)
Now, combine all these results together:
\[
x^2 - 2x + 8x - 16
\]
Now, combine the like terms \(-2x + 8x\):
\[
x^2 + (8 - 2)x - 16 = x^2 + 6x - 16
\]
So the polynomial \((x+8)(x-2)\) can be rewritten as:
\[
\boxed{x^2 + 6x - 16}
\]
Let's break this down:
1. **First**: Multiply the first terms:
\(x \cdot x = x^2\)
2. **Outside**: Multiply the outer terms:
\(x \cdot (-2) = -2x\)
3. **Inside**: Multiply the inner terms:
\(8 \cdot x = 8x\)
4. **Last**: Multiply the last terms:
\(8 \cdot (-2) = -16\)
Now, combine all these results together:
\[
x^2 - 2x + 8x - 16
\]
Now, combine the like terms \(-2x + 8x\):
\[
x^2 + (8 - 2)x - 16 = x^2 + 6x - 16
\]
So the polynomial \((x+8)(x-2)\) can be rewritten as:
\[
\boxed{x^2 + 6x - 16}
\]
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