Approximation:
V=a^3
dV/da=3a^2
dV=3a^2*da
dv=vfinal-vinitial=3*8^2*(7.99-8)=3*64*( -0.01)= -1.92 in^3
By the way exact value is: 7.99^3-8^3=510.082399-512= -1.917601 in^3
Use differentials to approximate the change in the volume of a cube when the side is decreased from 8 to 7.99 cm. (in cm^3)
Thank you so much!!
1 answer
1 answer