To determine the type of function represented by the given table of values, we will analyze the first and second differences of the \( y \) values.
Given Data
\[ \begin{array}{|c|c|} \hline x & y \ \hline -2 & -6 \ -1 & -6 \ 0 & -4 \ 1 & 0 \ 2 & 6 \ \hline \end{array} \]
First Differences
We will calculate the first differences, which are found by subtracting each \( y \) value from the next one.
- \( -6 - (-6) = 0 \)
- \( -6 - (-4) = -2 \)
- \( -4 - 0 = -4 \)
- \( 0 - 6 = -6 \)
Thus, the first differences are: \[ 0, -2, -4, -6 \]
Second Differences
Now, we calculate the second differences by subtracting each first difference from the next one.
- \( -2 - 0 = -2 \)
- \( -4 - (-2) = -2 \)
- \( -6 - (-4) = -2 \)
Thus, the second differences are: \[ -2, -2, -2 \]
Conclusion
- The first differences are not constant, which indicates this is not a linear function.
- The second differences are constant, which indicates the function is a quadratic function.
Therefore, the table of values represents a quadratic function.