Use back substitution to solve the system of linear equations

Question

x-2y+z=8
y+z=5
z=2

**I tried to solve it eventho im still confused/lost.
1=3 idk ugh

Answer 1

well, let's put z=2 into the 2nd

z=y + 2 = 5
y = 3
So now we know that z=2 and y = 3

now into the 1st:
x - 6 + 2 = 8
z = 12

So, where was your problem with this ?
Looks very very easy.

Answer 2

Thanks ...its easy for you because your good in math. IM not.