a/b/c = a/(bc)
so, we have
(3y-5)/5/(14/10 + 7/2 y)
= (3y-5)/(5*7(1/5 + 1/2 y))
= (3y-5)/(35*(2+5y)/10)
= 2(3y-5)/(7(2+5y))
Now subtract that from y and you have
7y(2+5y) - 2(3y-5)
-----------------------
7(5y+2)
(35y^2+8y+10)/(35y+14)
use any method to simplify the complex fraction.
y-(3y-5)/5/(14/10 + 7/2y)
the fraction simplifies to ___.
1 answer