algebraic method?
x+4y=14
3x+2y=12
multipy the first equation by 3
3x+12y=42
3x+2y=12
subtract the second equation from the first.
10y=30
y=3
put that value of y into either equation, and solve for x.
Use algebraic method to solve line 1 x+4y=14 line a 3x+2y=12
2 answers
x=2
1 answer