Use a variation model to solve for the unknown value.

The body mass index (BMI) of an individual varies directly as the weight of the individual and inversely as the square of the height of the individual. The body mass index for a 177-lb person who is 77 in. tall is 20.99. Determine the BMI for an individual who is 71 in. tall and 152 lb.
Round to 2 decimals

1 answer

The body mass index (BMI) can be expressed with the equation:

\[ \text{BMI} = k \frac{W}{H^2} \]

where:

  • \( W \) is the weight of the individual,
  • \( H \) is the height of the individual,
  • \( k \) is the constant of proportionality.

First, we will determine the constant \( k \) using the data provided for the individual who is 177 lbs and 77 in tall:

Given:

  • \( W = 177 \) lbs
  • \( H = 77 \) in
  • \( \text{BMI} = 20.99 \)

Substituting these values into the equation:

\[ 20.99 = k \frac{177}{77^2} \]

Calculating \( 77^2 \):

\[ 77^2 = 5929 \]

Substituting this back into the equation gives:

\[ 20.99 = k \frac{177}{5929} \]

To find \( k \), we rearrange the equation:

\[ k = 20.99 \cdot \frac{5929}{177} \]

Calculating \( \frac{5929}{177} \):

\[ \frac{5929}{177} \approx 33.487 \]

Now, multiplying by 20.99:

\[ k = 20.99 \cdot 33.487 \approx 702.85653 \]

Now that we have \( k \), we can calculate the BMI for the individual who is 71 in tall and weighs 152 lb.

Given:

  • \( W = 152 \) lbs
  • \( H = 71 \) in

Plugging these values back into the BMI formula:

\[ \text{BMI} = k \frac{W}{H^2} \]

Calculating \( 71^2 \):

\[ 71^2 = 5041 \]

Now substituting the values into the equation:

\[ \text{BMI} = 702.85653 \cdot \frac{152}{5041} \]

Calculating \( \frac{152}{5041} \):

\[ \frac{152}{5041} \approx 0.03015 \]

Now multiply by \( k \):

\[ \text{BMI} \approx 702.85653 \cdot 0.03015 \approx 21.15 \]

Rounding to two decimal places, we find:

\[ \text{BMI} \approx 21.15 \]

So, the BMI for an individual who is 71 inches tall and weighs 152 lbs is approximately 21.15.