Use a(t) = -32 ft/sec2 as the acceleration due to gravity. (Neglect air resistance.)

A ball is thrown vertically upward from a height of 4 feet with an initial velocity of 79 feet per second. How high will the ball go? (Round your answer to two decimal places.)

1 answer

h = -16t^2 + 79t + 4

we need the vertex of this downwards parabola
the t of the vertex = -b/2a
= -79/-32
= 79/32 sec

for that time
height = -16(79/32)^2 + (79/32)(79) + 4
= 197.796..
= 197.80 correct to 2 decimals

check my arithmetic