a(t) = -32
v(t) = 79 - 32t
h(t) = 4 + 79t - 16t^2
Now just find the vertex of that parabola, at t = 79/32
Use a(t) = -32 ft/sec2 as the acceleration due to gravity. (Neglect air resistance.)
A ball is thrown vertically upward from a height of 4 feet with an initial velocity of 79 feet per second. How high will the ball go? (Round your answer to two decimal places.)
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