Use a number line or your Desmos calculator for this problem. *You will want to hold down the ctrl key when clicking on the Desmos link, so you don't lose your place in this test. (1 point) The √40 is between and .

Answer 1

To find the approximate value of \(\sqrt{40}\), we can determine between which two whole numbers it lies.

First, we know the squares of some whole numbers:

• \(6^2 = 36\)
• \(7^2 = 49\)

Since \(36 < 40 < 49\), it follows that:

\[ 6 < \sqrt{40} < 7 \]

Thus, \(\sqrt{40}\) is between \(6\) and \(7\).

To be more specific, we can also approximate \(\sqrt{40}\):

Calculating the actual value, \(\sqrt{40} = \sqrt{4 \cdot 10} = 2\sqrt{10}\). Knowing \(\sqrt{10} \approx 3.16\), we can approximate:

\[ \sqrt{40} \approx 2 \cdot 3.16 \approx 6.32 \]

Therefore, you can conclude that:

\(\sqrt{40}\) is between \(6\) and \(7\).