To find Upton's final velocity after free falling for 2.60 seconds, we can use the equation:
v = u + at
Where:
v = final velocity
u = initial velocity (which is 0 m/s since Upton is free falling)
a = acceleration (-9.80 m/s)
t = time (2.60 seconds)
Plugging in the values:
v = 0 + (-9.80)(2.60)
v = -25.48 m/s
So, Upton's final velocity after free falling for 2.60 seconds is -25.48 m/s.
Next, to find how far Upton fell, we can use the equation:
s = ut + (1/2)at^2
Where:
s = distance fallen
u = initial velocity (0 m/s)
t = time (2.60 seconds)
a = acceleration (-9.80 m/s)
Plugging in the values:
s = (0)(2.60) + (1/2)(-9.80)(2.60)^2
s = 33.94 meters
Therefore, Upton fell a distance of 33.94 meters while riding the Power Tower at ValleyFair.
Upton Chuck is riding the Power Tower at ValleyFair. If Upton free falls for 2.60 seconds, what will be his final velocity and how far will he fall? (Remember acceleration is -9.80 m/s).
1 answer