UNIT 8

LESSON 3
Equations with Parentheses Quick Check

1 answer

1. Solve the equation: 3(x + 2) = 15.

First, distribute the 3 to the terms inside the parentheses:
3 * x + 3 * 2 = 15
3x + 6 = 15

Next, subtract 6 from both sides of the equation:
3x + 6 - 6 = 15 - 6
3x = 9

Finally, divide both sides of the equation by 3 to solve for x:
3x/3 = 9/3
x = 3

Therefore, the solution to the equation is x = 3.

2. Solve the equation: 2(3x - 1) = 10 + 4x.

First, distribute the 2 to the terms inside the parentheses:
2 * 3x - 2 * 1 = 10 + 4x
6x - 2 = 10 + 4x

Next, subtract 4x from both sides of the equation:
6x - 4x - 2 = 10 + 4x - 4x
2x - 2 = 10

Next, add 2 to both sides of the equation:
2x - 2 + 2 = 10 + 2
2x = 12

Finally, divide both sides of the equation by 2 to solve for x:
2x/2 = 12/2
x = 6

Therefore, the solution to the equation is x = 6.