Under the influence of the electric force of attraction, the electron in a hydrogen atom orbits around the proton on a circle of radius 5.3 x 10^-11 m. What is the orbital speed? What is the orbital period?

Answer 1

The centripetal force m V^2/r must equal the Coulomb attraction force ke^2/r^2.

Solve for v, the orbital speed.

The period will be

P = 2 pi r/ V