Let gg be the number of gigabytes Paisley can use while staying within her budget.
The total cost of Paisley's cell phone bill is given by:
Total Cost = $60 + $3(gg)
Since Paisley wants to keep her bill under $75 per month, we can write the inequality:
$60 + $3(gg) ≤ $75
Simplifying the inequality, we get:
$60 + $3(gg) - $60 ≤ $75 - $60
$3(gg) ≤ $15
gg ≤ 5
Therefore, the inequality which can be used to determine gg, the number of gigabytes Paisley can use while staying within her budget is gg ≤ 5.
Under her cell phone plan, Paisley pays a flat cost of $60 per month and $3 per gigabyte. She wants to keep her bill under $75 per month. Write and solve an inequality which can be used to determine gg, the number of gigabytes Paisley can use while staying within her budget.
11 answers
Audrey has $440 to spend at a bicycle store for some new gear and biking outfits. Assume all prices listed include tax.
She buys a new bicycle for $259.52.
She buys 2 bicycle reflectors for $3.07 each and a pair of bike gloves for $29.12.
She plans to spend some or all of the money she has left to buy new biking outfits for $72.61 each.
Write and solve an inequality which can be used to determine oo, the number of outfits Audrey can purchase while staying within her budget.
She buys a new bicycle for $259.52.
She buys 2 bicycle reflectors for $3.07 each and a pair of bike gloves for $29.12.
She plans to spend some or all of the money she has left to buy new biking outfits for $72.61 each.
Write and solve an inequality which can be used to determine oo, the number of outfits Audrey can purchase while staying within her budget.
Let oo be the number of outfits Audrey can purchase while staying within her budget.
The total cost of all the items Audrey has purchased and plans to purchase is given by:
Total Cost = $259.52 + 2($3.07) + $29.12 + $72.61(oo)
Audrey's budget is $440, so we can write the inequality:
$259.52 + 2($3.07) + $29.12 + $72.61(oo) ≤ $440
Simplifying the inequality, we get:
$259.52 + $6.14 + $29.12 + $72.61(oo) ≤ $440
$294.78 + $72.61(oo) ≤ $440
$72.61(oo) ≤ $440 - $294.78
$72.61(oo) ≤ $145.22
oo ≤ $145.22 / $72.61
oo ≤ 2
Therefore, the inequality which can be used to determine oo, the number of outfits Audrey can purchase while staying within her budget is oo ≤ 2. Audrey can purchase a maximum of 2 outfits while staying within her budget.
The total cost of all the items Audrey has purchased and plans to purchase is given by:
Total Cost = $259.52 + 2($3.07) + $29.12 + $72.61(oo)
Audrey's budget is $440, so we can write the inequality:
$259.52 + 2($3.07) + $29.12 + $72.61(oo) ≤ $440
Simplifying the inequality, we get:
$259.52 + $6.14 + $29.12 + $72.61(oo) ≤ $440
$294.78 + $72.61(oo) ≤ $440
$72.61(oo) ≤ $440 - $294.78
$72.61(oo) ≤ $145.22
oo ≤ $145.22 / $72.61
oo ≤ 2
Therefore, the inequality which can be used to determine oo, the number of outfits Audrey can purchase while staying within her budget is oo ≤ 2. Audrey can purchase a maximum of 2 outfits while staying within her budget.
what is the inquality
The inequality is:
$259.52 + 2($3.07) + $29.12 + $72.61(oo) ≤ $440
Simplified:
$294.78 + $72.61(oo) ≤ $440
$72.61(oo) ≤ $145.22
oo ≤ 2
$259.52 + 2($3.07) + $29.12 + $72.61(oo) ≤ $440
Simplified:
$294.78 + $72.61(oo) ≤ $440
$72.61(oo) ≤ $145.22
oo ≤ 2
Mariam has $560 to spend at a bicycle store for some new gear and biking outfits. Assume all prices listed include tax.
She buys a new bicycle for $275.67.
She buys 3 bicycle reflectors for $16.32 each and a pair of bike gloves for $24.39.
She plans to spend some or all of the money she has left to buy new biking outfits for $27.40 each.
Write and solve an inequality which can be used to determine xx, the number of outfits Mariam can purchase while staying within her budget.
She buys a new bicycle for $275.67.
She buys 3 bicycle reflectors for $16.32 each and a pair of bike gloves for $24.39.
She plans to spend some or all of the money she has left to buy new biking outfits for $27.40 each.
Write and solve an inequality which can be used to determine xx, the number of outfits Mariam can purchase while staying within her budget.
Let xx be the number of outfits Mariam can purchase while staying within her budget.
The total cost of all the items Mariam has purchased and plans to purchase is given by:
Total Cost = $275.67 + 3($16.32) + $24.39 + $27.40(xx)
Mariam's budget is $560, so we can write the inequality:
$275.67 + 3($16.32) + $24.39 + $27.40(xx) ≤ $560
Simplifying the inequality, we get:
$275.67 + $48.96 + $24.39 + $27.40(xx) ≤ $560
$349.02 + $27.40(xx) ≤ $560
$27.40(xx) ≤ $210.98
xx ≤ $210.98 / $27.40
xx ≤ 7
Therefore, the inequality which can be used to determine xx, the number of outfits Mariam can purchase while staying within her budget is xx ≤ 7. Mariam can purchase a maximum of 7 outfits while staying within her budget.
The total cost of all the items Mariam has purchased and plans to purchase is given by:
Total Cost = $275.67 + 3($16.32) + $24.39 + $27.40(xx)
Mariam's budget is $560, so we can write the inequality:
$275.67 + 3($16.32) + $24.39 + $27.40(xx) ≤ $560
Simplifying the inequality, we get:
$275.67 + $48.96 + $24.39 + $27.40(xx) ≤ $560
$349.02 + $27.40(xx) ≤ $560
$27.40(xx) ≤ $210.98
xx ≤ $210.98 / $27.40
xx ≤ 7
Therefore, the inequality which can be used to determine xx, the number of outfits Mariam can purchase while staying within her budget is xx ≤ 7. Mariam can purchase a maximum of 7 outfits while staying within her budget.
what is the inqaulity
The inequality is:
$275.67 + 3($16.32) + $24.39 + $27.40(xx) ≤ $560
Simplified:
$349.02 + $27.40(xx) ≤ $560
$27.40(xx) ≤ $210.98
xx ≤ 7
$275.67 + 3($16.32) + $24.39 + $27.40(xx) ≤ $560
Simplified:
$349.02 + $27.40(xx) ≤ $560
$27.40(xx) ≤ $210.98
xx ≤ 7
Which of the following sets of numbers could not represent the three sides of a triangle?
A. {11,19,32}
B. {11,23,31}
C. {8,18,24}
D. {7,22,27}
A. {11,19,32}
B. {11,23,31}
C. {8,18,24}
D. {7,22,27}
A set of numbers could not represent the three sides of a triangle if the sum of the lengths of any two sides is less than or equal to the length of the third side.
Lets verify for each set:
A. {11, 19, 32}
11 + 19 = 30
This sum is less than 32, so it could be a triangle.
B. {11, 23, 31}
11 + 23 = 34
This sum is greater than 31, so it could be a triangle.
C. {8, 18, 24}
8 + 18 = 26
This sum is less than 24, so it could not be a triangle.
D. {7, 22, 27}
7 + 22 = 29
This sum is greater than 27, so it could be a triangle.
Therefore, C. {8, 18, 24} could not represent the three sides of a triangle.
Lets verify for each set:
A. {11, 19, 32}
11 + 19 = 30
This sum is less than 32, so it could be a triangle.
B. {11, 23, 31}
11 + 23 = 34
This sum is greater than 31, so it could be a triangle.
C. {8, 18, 24}
8 + 18 = 26
This sum is less than 24, so it could not be a triangle.
D. {7, 22, 27}
7 + 22 = 29
This sum is greater than 27, so it could be a triangle.
Therefore, C. {8, 18, 24} could not represent the three sides of a triangle.
3 answers