To determine the starting amount of water based on the reaction and the masses of hydrogen and oxygen collected, we can use the law of conservation of mass. According to this law, the mass of the reactants should equal the mass of the products.
From the balanced equation: \[ 2H_2O \rightarrow 2H_2 + O_2 \]
This indicates that 2 moles of water produce 2 moles of hydrogen and 1 mole of oxygen.
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Calculate the molar masses:
- Molar mass of \( H_2 \) (hydrogen) = 2 g/mol
- Molar mass of \( O_2 \) (oxygen) = 32 g/mol
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Calculate the total mass of gases collected:
- Mass of hydrogen collected = 96 g
- Mass of oxygen collected = 404 g
- Total mass of gases = 96 g + 404 g = 500 g
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The law of conservation of mass states that the mass of the starting substances (water) should equal the mass of the products (hydrogen and oxygen):
- Mass of water = Mass of hydrogen + Mass of oxygen = 500 g
In this case, Student B is correct because the law of conservation of matter supports that the total mass of water that was split should equal the total mass of the gases collected.
So, the correct answer is: Student B, because the law of conservation of matter.