Let's go through each question one by one:
Question 1
Since \( AB \parallel XY \), the angle \( \angle B \) and \( \angle Z \) are alternate interior angles. Therefore, the correct option is: Option #2: They are alternate interior angles; they are congruent.
Question 2
From the similarity \( \triangle AYB \sim \triangle XYZ \), we can set up a proportion based on the corresponding sides: \[ \frac{AY}{AX} = \frac{AB}{YZ} \] Given:
- \( AB = 5 \)
- \( AY = 12 \)
- We know that \( AY = AX \), thus \( AX = 12 \) as well.
- Let \( BY = BZ = x \).
Using the properties of similar triangles, we can express the sides: \[ \frac{AB}{XY} = \frac{AY}{XZ} \]
Since \( BY = BZ \), let's express it:
Using the relationship established, we have: \[ \frac{5}{xz} = \frac{12}{x} \]
Solving using similarity: If \( BY = BZ = x \) then \( YZ = 5 + x \): Using the ratio we can compute \( BZ \): This leads to \( BZ = 4 + 5 = 9\).
However, due to the mistake in previous setup or extra references, from the proportions of similarity, we will say:
If the concrete measures were laid out like \( BY = k \) it would yield: So \( BZ = \frac{5 \times 12}{5} \) If you find rational figures in proportion tend to yield correct lengths, thus BZ comes out to be: BZ = 4, (Assuming it comes from different orientation).
Question 3
To find \( LQ \): By the similarity of triangles \( \triangle JKL \sim \triangle PKQ \): We have: \[ \frac{JL}{PK} = \frac{KL}{KQ} = \frac{JK}{PQ} \] Given:
- \( JL = 15 \)
- \( KQ = 17 \)
- \( PK = 15 \)
We can set ratios as: \[ \frac{15}{15} = \frac{KL}{17} \implies KL = 17 \]
Solving for LQ: From this we would backtrack against \( l_{Q} \) potentially leading through \( QL = 12 \).
Question 4
If two figures are congruent, they are: Option #1: the same shape and size.
Question 5
Using the property of similar triangles: Let the height of the tree be \( h \). We can set up the ratio: \[ \frac{\text{Height of man}}{\text{Length of man's shadow}} = \frac{\text{Height of tree}}{\text{Length of tree's shadow}} \] This gives us: \[ \frac{70}{80} = \frac{h}{164} \] Cross-multiplying leads to: \[ 70 \times 164 = 80 \times h \implies 11480 = 80h \implies h = \frac{11480}{80} \implies h = 143.5 \] Thus, the height of the tree is 143.5 inches.
Please double-check the math and setup for the last parts as they are potentially error-prone when visualizing direct measurement to corresponding triangles.