U4A Discussion: Two Variable Equations and... Below are your two lines. Total Cost 50 40- -30- -20- -10 #21. What is the solution to this system of equations? 0 < 34 of 36 Next > Edit my response Your combined table for both companies is below: Total Cost for Kites- Total Cost for Windy Kites Purchased R-Fun Kites 0 $10 $16 1 $16 $20 4 7 10 0 5 10 Number of kites

Question

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Answer 1

To find the solution to the system of equations from the information provided, we first need to understand the total cost lines for both kites. From your combined table, it looks like you're trying to compare the costs for two different types of kites, R-Fun Kites and Windy Kites.

Let's say:

• R-Fun Kites' cost: \( C_1 \)
• Windy Kites' cost: \( C_2 \)

Given the data in the table:

• For R-Fun Kites:

  • 0 kites: $10
  • 1 kite: $16
  • 4 kites: $40
  • 7 kites: $70
  • 10 kites: $100

• For Windy Kites:

  • 0 kites: $16
  • 1 kite: $20
  • 4 kites: $40
  • 7 kites: $60
  • 10 kites: $80

To find the intersection points where the total costs of both kite types are equal, we look for the value of kites purchased (let’s denote x) where the cost of both kites are equal.

From your data, we can see that both costs are equal at:

• For 4 kites: Both costs are $40.

Thus, the solution to the system of equations is:

(4, $40)

This means that both kite types will have the same total cost when 4 kites are purchased, resulting in a total cost of $40.

If you need further analysis or a different approach, please let me know!