Let's analyze Tyrianne's solution step by step to identify any errors.
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Step 1: \[ \frac{1}{2}(x+4)^2 - 3 = 29 \] Tyrianne correctly adds 3 to both sides: \[ \frac{1}{2}(x+4)^2 = 32 \]
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Step 2: She then multiplies both sides by 2 to eliminate the fraction, leading to: \[ (x+4)^2 = 64 \] (This is the error—not \(16\), as she incorrectly wrote.)
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Step 3: Tyrianne takes the square root: \[ x+4 = \pm 8 \]
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Step 4: Solving for \(x\), she finds: \[ x = 4 \quad \text{or} \quad x = -12 \]
Based on our analysis, the error occurred in Step 2 where she incorrectly stated \((x+4)^2 = 16\) instead of \((x+4)^2 = 64\).
Therefore, the correct choice is: (Choice B) Step 2.