To determine how long Tyra's family will be able to spend in Millersville while staying within their budget of less than $60, we can set up an inequality.
Let \( h \) be the number of hours they spend parking. The total cost for the outing can be represented as the sum of the movie cost and the parking cost:
- Cost of the movie: $36
- Parking cost: $4 per hour, so for \( h \) hours, it will be \( 4h \).
The total cost can be expressed as:
\[ \text{Total Cost} = 36 + 4h \]
We want this total to be less than $60:
\[ 36 + 4h < 60 \]
Now, we can solve this inequality step-by-step:
- Subtract 36 from both sides:
\[ 4h < 60 - 36 \]
\[ 4h < 24 \]
- Divide both sides by 4:
\[ h < 6 \]
This means the family can spend less than 6 hours on parking. Since they also need to consider that the movie is over 2 hours long, the total time spent in Millersville will be the movie time plus parking time.
If we denote the time spent watching the movie as \( m \) (where \( m > 2 \)), the total time spent in Millersville will be:
\[ \text{Total time} = m + h \]
Given that \( h < 6 \):
- If \( m \) is at least 2 hours long, the family has at least \( 2 + h < 2 + 6 = 8 \) hours total in Millersville, with some total time slightly longer than 8 hours (if they watch a movie that is just over 2 hours).
In conclusion, the inequality for the parking hours is \( h < 6 \), meaning the family has a total of less than 8 hours in Millersville, factoring in the movie duration as well.
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