To find the initial amount of bacteria, we evaluate the function \( s(n) \) at \( n = 0 \):
\[ s(0) = 20 \cdot b^0 = 20 \cdot 1 = 20 \]
Thus, there were initially 20 bacteria.
Next, to find the hourly percent growth rate when \( b = 1.85 \), we can calculate the growth rate using the formula for percent growth rate:
\[ \text{Percent Growth Rate} = (b - 1) \cdot 100 \]
Substituting \( b = 1.85 \):
\[ \text{Percent Growth Rate} = (1.85 - 1) \cdot 100 = 0.85 \cdot 100 = 85 \]
Thus, the hourly percent growth rate of the bacteria would be 85%.
In summary:
Initial amount of bacteria: 20
Hourly percent growth rate: 85