Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).

Question

Mr. Schwartz builds toy cars. He begins the week with a supply of 85 wheels, and uses 4 wheels for each car he builds. Mr. Schwartz plans to order more wheels once he has fewer than 40 wheels left.

The inequality that can be used to find the number of cars, x, Mr. Schwartz builds before he places an order for more wheels is
−
x < 40.

Mr.Schwartz will need to order more wheels after building
cars.

Answer 1

To determine the number of cars Mr. Schwartz can build before he places an order for more wheels, we need to set up the inequality based on his initial supply of wheels and the wheels used per car.

He starts with 85 wheels and uses 4 wheels for each car, and he will order more once he has fewer than 40 wheels left.

The inequality is set up as follows:

85 - 4x < 40

Now, to find out how many cars he can build before placing the order, we can solve this inequality:

1. Start with the inequality: 85 - 4x < 40

2. Subtract 85 from both sides: -4x < 40 - 85 -4x < -45

3. Divide both sides by -4 (remember to reverse the inequality sign): x > 45 / 4 x > 11.25

Since Mr. Schwartz cannot build a fraction of a car, we take the integer part, which means he can build a maximum of 11 cars.

Therefore, Mr. Schwartz will need to order more wheels after building:

11 cars.