M*g = 310kg * 9.8N/kg = 3,038 N. = Wt. of the crate = Normal force(Fn).
Fap-Fk = M*a
(440+230)-Fk = M*0 = 0
670 - Fk = 0
Fk = 670 N. = Force of kinetic friction
uk = Fk/Fn = 670/3038 = 0.221
Two workers are sliding 310kg crate across the floor. One worker pushes forward on the crate with a force of 440N while the other pulls in the same direction with a force of 230N using a rope connected to the crate. Both forces are horizontal, and the crate slides with a constant speed. What is the crate's coefficient of kinetic friction on the floor?
2 answers
.221
2 answers