Two workers are pushing on the same large crate. One worker pushes east with a force of 875 N, while the other worker pushes north with a force of 960 N. Friction between the crate and the floor is directed west with a force of 80 N and south with a force of 105 N. Assuming drag due to air resistance is negligible, what are the total north-south net forces and the total east-west net forces acting on the crate, causing it to accelerate across the floor?(1 point)

Question

Responses

855 N to the north and 795 N to the east
855 N to the north and 795 N to the east

795 N to the north and 855 N to the east
795 N to the north and 855 N to the east

795 N to the south and 855 N to the west
795 N to the south and 855 N to the west

855 N to the south and 759 N to the west

Answer 1

To find the net forces acting on the crate, we need to calculate the total forces in the north-south and east-west directions, taking into account the forces applied by the workers and the friction forces acting on the crate.

North-South Forces:

1. Worker pushing north: 960 N
2. Friction force acting south: 105 N

Net north-south force: \[ F_{\text{net, north-south}} = F_{\text{north}} - F_{\text{south}} = 960 , \text{N} - 105 , \text{N} = 855 , \text{N} \text{ (to the north)} \]

East-West Forces:

1. Worker pushing east: 875 N
2. Friction force acting west: 80 N

Net east-west force: \[ F_{\text{net, east-west}} = F_{\text{east}} - F_{\text{west}} = 875 , \text{N} - 80 , \text{N} = 795 , \text{N} \text{ (to the east)} \]

Summary of Net Forces:

• Total north-south net force: 855 N to the north
• Total east-west net force: 795 N to the east

Therefore, the answer is:

855 N to the north and 795 N to the east.