<A + <B = 67o + 58 - 125o.
<C = 180-125 = 55o.
Using Law of Sine:
Sin55/21 = Sin58/AC. AC = ?.
Sin55/21 = Sin67/BC. BC = ?.
<A and <B are the angles between the wires and gnd.
<C is formed by the wires at the point of connection to the pole.
Two wires support an electricity pole. if the wires make angles of 58°and 67° with the ground and |AB|=21m, calculate the lengths of the wires
5 answers
another way to do it is to use the cot function. If the pole's height is h, then
h cot67° + h cot 58° = 21
So, h = 21/(cot67°+cot58°)
Then using h, the lengths of the wires are
h csc 67° and h csc 58°
h cot67° + h cot 58° = 21
So, h = 21/(cot67°+cot58°)
Then using h, the lengths of the wires are
h csc 67° and h csc 58°
What of the diagram
The diagram of the question and complete solution
What of the diagram.