Two wires support an electricity pole. if the wires make angles of 58°and 67° with the ground and |AB|=21m, calculate the lengths of the wires

5 answers

<A + <B = 67o + 58 - 125o.

<C = 180-125 = 55o.

Using Law of Sine:
Sin55/21 = Sin58/AC. AC = ?.

Sin55/21 = Sin67/BC. BC = ?.

<A and <B are the angles between the wires and gnd.
<C is formed by the wires at the point of connection to the pole.
another way to do it is to use the cot function. If the pole's height is h, then

h cot67° + h cot 58° = 21
So, h = 21/(cot67°+cot58°)

Then using h, the lengths of the wires are
h csc 67° and h csc 58°
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