Two watermelons fall off a kitchen counter. The masses and speeds of the fruits are in the table. How do the kinetic and/or potential energies of the fruits compare

1 answer

To compare the kinetic and potential energies of the two watermelons, we need to consider the following:

  1. Potential Energy (PE): This energy is determined by the height of an object above the ground, given by the formula: \[ PE = mgh \] where:

    • \(m\) is the mass of the object,
    • \(g\) is the acceleration due to gravity (\(9.81 , \text{m/s}^2\) on Earth),
    • \(h\) is the height from which the object falls.
  2. Kinetic Energy (KE): This energy is determined by the speed of the object, given by the formula: \[ KE = \frac{1}{2}mv^2 \] where:

    • \(m\) is the mass of the object,
    • \(v\) is the speed of the object.

To perform a comparison, you'll need the masses \(m_1\) and \(m_2\) and speeds \(v_1\) and \(v_2\) of the two watermelons, as well as the height \(h\) from which they fell.

Steps to Compare Energies

  1. Calculate Potential Energy: If both watermelons fell from the same height, their potential energies can be compared using their masses: \[ PE_1 = m_1gh \quad \text{and} \quad PE_2 = m_2gh \] The watermelon with the greater mass will have more potential energy, assuming the heights are equal.

  2. Calculate Kinetic Energy: Use the masses and speeds to find kinetic energies: \[ KE_1 = \frac{1}{2}m_1v_1^2 \quad \text{and} \quad KE_2 = \frac{1}{2}m_2v_2^2 \] The watermelon with the greater mass and/or higher speed will have more kinetic energy.

Comparison Summary:

  • If the watermelons have different masses, the one with the greater mass has more potential energy before falling.
  • If both have the same height but different speeds upon reaching the ground, the one with the higher speed has more kinetic energy upon impact.
  • At the moment of impact, potential energy decreases to zero (assuming they are at ground level), converting to kinetic energy.

If you provide the specific masses, speeds, and height information, I can help you perform the exact calculations!