The magnitude of a cross product of A and B is
|A| |B| sin theta,
where |A| and |B| are the magnitudes of A and B, which are both 3.
The magnitude of 5 k + 2i is sqrt(2^2 + 5^2) = sqrt 29
That means sin theta = sqrt(29)/9 = 0.59835
theta = 36.75 degrees
Two vectors A. and B have magnitude A = 3.00 and B = 3.00. Their vector product is A x B= -5.00k + 2.00i. What is the angle between A and B?
4 answers
hey, thanks a lot.
36.8
Hello Can you explain why you had to find the magnitude of 5k+2i?
1 answer