Two urns both contain green balls and red balls. Urn I contains 6 green balls and 4 red balls and Urn I contains 8 green balls and 7 red balls. A ball is drawn from each urn. What is the probability that both balls are red?

1 answer

The probability of drawing a red ball from Urn I is 4/10 = 2/5. The probability of drawing a red ball from Urn II is 7/15.

The probability of both events happening (drawing a red ball from both urns) is equal to the product of their probabilities:

P(both red) = P(red from Urn I) × P(red from Urn II)
P(both red) = (2/5) × (7/15)
P(both red) = 14/75

Therefore, the probability of drawing two red balls is 14/75.