I will assume the octagon is regular, so each side is 3.5/8 = 7/16.
Now just divide the octagon into eight isosceles triangles, each with base 7/16 and vertex angle 45°.
The area of each triangle is easy to do, and just multiply it by 8.
Two unit squares share the same center. The overlapping region of the two squares is an octagon with perimeter 3.5. What is the area of the octagon?
I don't know how to do this. Could you please help me?
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