To determine which statements are true regarding the speeds of Velma and Justine, we can analyze their rates based on Velma's equation and the graph representing Justine's performance.
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Velma's speed: The equation \( y = 4x \) indicates that Velma travels 4 meters for every minute (since for every minute \( x \), the distance \( y \) is increased by 4 meters). Thus, Velma's speed is 4 meters per minute.
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Justine's speed: To determine Justine's speed from her graph, we examine her distance at specific times. If the graph shows that Justine's distance is, for example, 6 meters after 1 minute, then her speed would be 6 meters per minute. We would need to evaluate it by looking at her distance over a certain time span.
Now, let's analyze the options based on their speeds:
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A. Justine is twice as fast as Velma.: If Justine is moving at 8 m/min, then this statement would be true. If she's moving at 6 m/min (or less), it would be false. We need the graph to decide.
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B. Justine is half as fast as Velma.: This is true if Justine moves at 2 m/min. It requires examination of Justine's speed based on the graph.
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C. Justine and Velma have the same speed.: This is true if Justine's distance over time equals 4 m/min. We need the graph to decide.
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D. Justine moves a greater distance than Velma each minute.: This would be true if Justine’s speed exceeds 4 m/min.
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E. Justine moves a shorter distance than Velma each minute.: This would be true if Justine's speed is less than 4 m/min.
Without the visual representation of Justine's graph, I can't specifically determine her distance or speed values. You would need to identify Justine's speed from the graph to accurately choose which of these statements are true.
In a hypothetical scenario:
- If Justine is shown to travel 6 meters in 1 minute, then A is true, E is false, and so on.
Please refer to the graph to accurately compare Justine's distance over time to Velma's fixed rate.