Two Tugboats pull a disabled supertanker. Each tugboat exerts a constant force 1.8x10^6 N, one at 10° west of North and other at 10° east of north, as they pull the tanker 0.50km towards north. The mass of the tanker is 2.20x10^8 kg. What is the total work the tugboats do to move the tanker?

Answer 1

10o W. of N. = 100o CCW.
10o E. of N. = 80o CCW.

Fr = 1.8*10^6[100o] + 1.8*10^6[80o]=-3.126*10^5+1.773*10^5i + 3.126^10^5+1.773*10^5i = 3.546*10^5i = 3.546*10^5[90o] = 3.546*10^5N., Due North. = Resultant force.

Work = Fr*d = 3.546*10^5 * 500 =