Two triangles used in an art project are similar. The sides of the smaller triangle have lengths of 6 in., 7 in., and 12 in. The perimeter of the larger triangle is 75 in. What is the length of the shortest side of the larger triangle?(1 point)

Question

in.

Answer 1

The ratio of corresponding side lengths in similar triangles is equal. Let's set up a proportion using the sides of the smaller and larger triangles.

Let x be the length of the shortest side of the larger triangle.

Using the side lengths given for the smaller triangle, the proportion is:

6/7 = x/75

Cross multiplying, we get:

6 * 75 = 7 * x

450 = 7x

Dividing both sides by 7, we find:

x = 64.29

Therefore, the length of the shortest side of the larger triangle is approximately 64.29 inches.