each side of the big one is 4 times the one in the small triangle
4a+4b+4c = 4(a+b+c)
the altitude of the big one is 4 timess the altitude of the small one
(1/2)(4h)(4b) = (16) (1/2) a b
Two triangles are similar. The ratio of their corresponding sides
1:4.
1. Find the ratio of their perimeters
2. What is the ratio of their areas
2 answers
The ratio of the perimeters of two similar triangles is the same as the ratio of their corresponding sides.
In this case
P1 : P2 = 1 : 4
The ratio of the area of two similar triangles is proportional to square of the ratio of their corresponding sides.
In this case
A1 : A2 = ( 1 : 4 )² = 1 / 16
In this case
P1 : P2 = 1 : 4
The ratio of the area of two similar triangles is proportional to square of the ratio of their corresponding sides.
In this case
A1 : A2 = ( 1 : 4 )² = 1 / 16
3 answers