two trees x and y are 100m apart and y is due east of x.the bearing of a house z from x is 145degree and 225 degree. which tree is nearest to the house and by how many meters

Answer 1

draw the triangle XYZ
∠X = 55°
∠Y = 45°
∠X > ∠Y so YZ > XZ

∠Z = 80°
Now use the law of sines to find both XZ and YZ and their difference

Answer 2

YZ/sinX = XY/sinZ,
YZ/sin55 = 100/sin80,
YZ = 83.2 m.

XZ/sin45 = XY/sin80,
XZ/sin45 = 100/sin80,
XZ = ?

Answer 3

lamara muhammad