speed of slower train --- x km/h
speed of faster train ---- x+20 km/h
6 minutes = 6/60 or 1/10 hour
(1/10)x + (1/10)(x+20) = 11
times 10
x + x+20 = 110
2x = 90
x = 45
the slower train goes at 45 km/h
the faster at 65 km/h
Two trains, Aand B , leave a train station at the same time but in different directions, one towards east and the other towards west. Train B travels 20km/h faster than train A. After 6 minutes, the two trains are 11 km apart. Find the average speed of each train.
1 answer
1 answer