Two towers P and Q are 600m apart with P being due east of Q. A church is on a bearing of 210 degrees from P and 125 degrees from Q. Find the distance of the church from P and Q.

Answer 1

I labelled the position of the church as C.
angle C = 85°

by the sine law:
CP/sin35 = 600/sin85
CP = 600sin35°/sin85° = appr 345.5 m

you do CQ