2(x+4) < 3(x+7) - 4
Solve for x.
Two times the sum of a number and four is no more than three times the sum of the number and seven decreased by four.
3 answers
2(x+4) <= 3(x+7) - 4.
2x+8 <= 3x+21 - 4
-x <= 9
Divide both sides by -1and reverse inequality sign:
X >= -9.
2x+8 <= 3x+21 - 4
-x <= 9
Divide both sides by -1and reverse inequality sign:
X >= -9.
Two times a number decreased by three is between -33 and 33.
12 answers