Two thin, infinitely long, parallel wires are lying on the ground a distance d=3cm apart. They carry a current Io=200A going into the page. A third thin, infinitely long wire with mass per unit length λ=5g/m carries current I going out of the page. What is the value of the current I in amps in this third wire if it is levitated above the first two wires at height h=10cm above them and at a horizontal position midway between them?

Answer 1

draw the forces, there's repulsion between the two equal wire against the third one

We have:
F = [uo.I1.I2/(2.pi.d)]*Ltotal

2*F*sin(a)= m*g = lamba*Ltotal*g

sin(a)=h/0.5d

Replace the values and you'll I.

By the way, have you done the one with the thick metal slab?

Answer 2

have you got the answer?

Answer 3

hai anonymous ,i stuck on dis question if u done for it plz help ???