To get the same solution for both systems, the two systems must be equivalent. This means that the two equations in the second system must be multiples of the corresponding equations in the first system.
Comparing the equations in the first system, we can see that multiplying the second equation by 2 will give us the second equation in the second system:
2(x+y) = 2(2)
2x+2y = 4
Therefore, the value of c needs to be 2.
Two systems of equations are shown:
4x+y=−1
x+y=2
and
8x+2y=−2
−4x+cy=−8
What would the value of c need to be to get the same solution for both systems?
(1 point)
Responses
1
1
-2
-2
-4
-4
4
4
2
1 answer
1 answer