Two students push on the opposite sides of a crate, with the force applied by each student in newtons (N), as shown in the diagram.

Question

40 newtons.
53 newtons.

Assuming the crate is on a frictionless surface, describe the effect of these forces on the crate.
Will the crate move toward the left, toward the right, or not at all?
What is the direction and the magnitude of the net force on the crate?
Review the diagram carefully. Then enter your response in the box provided.

Answer 1

In this scenario, two students apply forces on opposite sides of a crate: one applies a force of 40 newtons to the left, and the other applies a force of 53 newtons to the right.

1. Net Force Calculation: To find the net force acting on the crate, we need to subtract the smaller force from the larger force, while keeping track of the direction: \[ \text{Net Force} = \text{Force to the right} - \text{Force to the left} = 53 , \text{N} - 40 , \text{N} = 13 , \text{N} \]

2. Direction of the Net Force: Since the net force is positive and greater than zero, the direction of the net force is toward the right.

3. Effect on the Crate: Because there is a net force acting to the right, the crate will accelerate in that direction.

In summary, the crate will move toward the right with a net force of 13 newtons in that direction.