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Two students in bumper cars want to prove conservation of momentum. They collide their bumper cars. The first bumper car has a...Question
                Two students in bumper cars want to prove conservation of momentum. They collide their bumper cars. The first bumper car has a mass of 120 kg and was moving with a velocity of 4.0 m/s before the collision and with a velocity of −2.0 m/s after the collision. The second bumper car has a mass of 90 kg and was moving at a velocity of −5.0 m/s before the collision. To prove conservation of momentum, what must the velocity of the second bumper car be after the collision?(1 point) Responses 3.0 m/s 3 point 0 meters per seconds 2.7 m/s 2 point 7 meters per seconds 1.0 m/s 1 point 0 meters per seconds 2.3 m/s
            
            
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                    Answered by
            GPT-4o mini
            
    To prove conservation of momentum, we can use the principle that the total momentum before the collision must equal the total momentum after the collision. 
Let's denote:
- Mass of the first bumper car \( m_1 = 120 \, \text{kg} \)
- Initial velocity of the first bumper car \( u_1 = 4.0 \, \text{m/s} \)
- Final velocity of the first bumper car \( v_1 = -2.0 \, \text{m/s} \)
- Mass of the second bumper car \( m_2 = 90 \, \text{kg} \)
- Initial velocity of the second bumper car \( u_2 = -5.0 \, \text{m/s} \)
- Final velocity of the second bumper car \( v_2 \) (this is what we need to find)
First, we calculate the total momentum before the collision:
\[
\text{Total momentum before} = m_1 u_1 + m_2 u_2
\]
\[
= (120 \, \text{kg} \times 4.0 \, \text{m/s}) + (90 \, \text{kg} \times -5.0 \, \text{m/s})
\]
\[
= 480 \, \text{kg m/s} - 450 \, \text{kg m/s}
\]
\[
= 30 \, \text{kg m/s}
\]
Next, we calculate the total momentum after the collision:
\[
\text{Total momentum after} = m_1 v_1 + m_2 v_2
\]
\[
= (120 \, \text{kg} \times -2.0 \, \text{m/s}) + (90 \, \text{kg} \times v_2)
\]
\[
= -240 \, \text{kg m/s} + 90 v_2
\]
Now, we set the total momentum before equal to the total momentum after:
\[
30 \, \text{kg m/s} = -240 \, \text{kg m/s} + 90 v_2
\]
Solving for \( v_2 \):
\[
30 + 240 = 90 v_2
\]
\[
270 = 90 v_2
\]
\[
v_2 = \frac{270}{90} = 3.0 \, \text{m/s}
\]
Therefore, the velocity of the second bumper car after the collision must be **3.0 m/s**.
    
Let's denote:
- Mass of the first bumper car \( m_1 = 120 \, \text{kg} \)
- Initial velocity of the first bumper car \( u_1 = 4.0 \, \text{m/s} \)
- Final velocity of the first bumper car \( v_1 = -2.0 \, \text{m/s} \)
- Mass of the second bumper car \( m_2 = 90 \, \text{kg} \)
- Initial velocity of the second bumper car \( u_2 = -5.0 \, \text{m/s} \)
- Final velocity of the second bumper car \( v_2 \) (this is what we need to find)
First, we calculate the total momentum before the collision:
\[
\text{Total momentum before} = m_1 u_1 + m_2 u_2
\]
\[
= (120 \, \text{kg} \times 4.0 \, \text{m/s}) + (90 \, \text{kg} \times -5.0 \, \text{m/s})
\]
\[
= 480 \, \text{kg m/s} - 450 \, \text{kg m/s}
\]
\[
= 30 \, \text{kg m/s}
\]
Next, we calculate the total momentum after the collision:
\[
\text{Total momentum after} = m_1 v_1 + m_2 v_2
\]
\[
= (120 \, \text{kg} \times -2.0 \, \text{m/s}) + (90 \, \text{kg} \times v_2)
\]
\[
= -240 \, \text{kg m/s} + 90 v_2
\]
Now, we set the total momentum before equal to the total momentum after:
\[
30 \, \text{kg m/s} = -240 \, \text{kg m/s} + 90 v_2
\]
Solving for \( v_2 \):
\[
30 + 240 = 90 v_2
\]
\[
270 = 90 v_2
\]
\[
v_2 = \frac{270}{90} = 3.0 \, \text{m/s}
\]
Therefore, the velocity of the second bumper car after the collision must be **3.0 m/s**.
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