net force=mass*a
16.5-3.7=(13.5) a
solve for a.
then,
vf=a*t
Two Students are pulling on a box initially at rest with a mass of 13.5 kg on a frictionless surface. Student #1 is applying a force of 16.5 N to the left while student #2 is apply a force of 3.7 N to the right. Find the velocity of the box after 6 sec
2 answers
f=ma
16.5-3.7=<13.5*9.8m/s =-
16.5-3.7=<13.5*9.8m/s =-