Two students are on a balcony 22 m above the street. One student throws a ball vertically downward at 15.5 m/s; at the same instant, the other student throws a ball vertically up- ward at the same speed. The second ball just misses the balcony on the way down.

Question

Two students are on a balcony 22 m above the street. One student throws a ball vertically downward at 15.5 m/s; at the same instant, the other student throws a ball vertically up- ward at the same speed. The second ball just misses the balcony on the way down.
How far apart are the balls 0.357 s after they are thrown? The acceleration of gravity is 9.8 m/s2 .

Chanz · Answer

x1 = 22 - 15.5(.357) - 4.9(.357^2) x2 = 22 + 15.5(.357) - 4.9(.357^2) Find the diff.